The next episode of "Steven Universe" season 3 will see Steven and the rest of the gems exploring Beta Kindergarten. On their exploration, they discovered Jasper's amazing origin.
The Perfect Creation
"Steven Universe" season 3, episode 22 titled "Beta: Part 1" will unveil Jasper's remarkable origin. As fans initially speculated, the spotlight will be focused on Jasper this season. Aside from revealing Jasper's origin, the episode will also reveal exciting details about Beta Kindergarten.
"Steven Universe" season 3, episode 22 will discover the backstory of Beta Kindergarten. Spoilers say that Beta Kindergarten was actually a fast replacement for the Kindergarten Homeworld, where Quartz soldiers were created during the war. Steven and the gang will stumble upon something that will lead them to believe that Jasper is actually a perfect creation according to Steven Universe Wiki. This will create conflicting emotions in Amethyst.
Steven Universe Celebrates 100 Episodes With One Hell of a Twist https://t.co/PdmiTBHUn3
— CartoonNetworkPR (@CartoonNetPR) August 8, 2016
'Steven Universe' Explores Beta Kindergarten
"Steven Universe" season 3, episode 22 will see Steven and Amethyst paying visit to their friends, Peridot and Lapis, at the countryside. Fans will see that Lapis and Peridot have created a museum and an aquarium made of objects from their past. Peridot then hears of Amethyst's plans of retribution towards Jasper. This will prompt Peridot to bring Amethyst and Steven to Beta Kindergarten where Jasper was made.
However, Steven and the Gems soon discovered strange markings in Beta Kindergarten. They soon discovered corrupted Gems kept in cages. Jasper then emerges, prompting them to suspect Jasper for all the kept Gems. Then they stumble upon a suprising perfect exit that will lead them to believe that Jasper is an ultimate quartz. Spoilers hint of a duel between Jasper and Amethyst in "Steven Universe" season 3. However, with Jasper being a perfect gem, fans are speculating that Jasper may be more an ally instead of the enemy.