Royal Christmas celebration is one of the most anticipated events for the followers of Kate Middleton and Prince William. Now that Prince Harry has officially announced his relationship with girlfriend Meghan Markle, fans are also curious if the "Suits" actress is invited to attend the royal family gathering.
While there are rumors that Meghan Markle is not invited to the royal Christmas celebration, persons concerned has still to comment. Kate Middleton and Meghan Markle's alleged feud have sparked more rumors that the actress is not invited to celebrate the joyous event in spite of Prince Harry's clamor.
Some fans may be curious what is in store for Kate Middleton and Meghan Markle should they be able to attend the royal Christmas celebration. Well, the tradition usually happens at the Sandringham House in Norfolk where almost all royal family members get together. Fans are excited to know if Prince Harry can tag along with his new girlfriend, Meghan Markle.
According to a report by The Telegraph, Kate Middleton and Prince William, and their children Prince George and Princess Charlotte, will not be joining the royal Christmas celebration this year. Instead, the Duchess of Cambridge and her family will spend the Christmas with the Middleton family. Pippa Middleton and brother James Middleton are also expected to join the private celebration. Without Kate Middleton, some are thinking of the possibility that Meghan Markle might join the young prince for Christmas.
However, Meghan Markle was seen leaving London just recently making people believe that the American actress will not be spending the royal Christmas celebration with boyfriend Prince Harry. Meghan Markle had spent a couple of days with Prince Harry at Nottingham Cottage at Kensington Palace. Do you think Kate Middleton and Meghan Markle's alleged feud was the reason why the 35-year-old actress is going to Los Angeles for Christmas? Tell us what you think and stay tuned to GamenGuide for the latest news and update of Kate Middleton and Meghan Markle feud.